الأجوبة
HCOOH + H2O ↔ HCOO- + H3O+
(حمض1) (أساس2) (أساس مرافق1) (حمض مرافق2)
PH + POH = 14
POH = 14 – 2 = 12
[H3O+] = √Ca.Ka
10-2 = √Ca*2*10-4
Ca = 5*10-1 mol/L
[H3O]’ = 10-PH = 10-3 mol/L
[H3O+]’ = √Ca’.Ka
10-3 = √Ca’*2*10-4
Ca’ = 5*10-3 mol/L
C1.V1 = C2.V2
0.5*10 = 0.005*V2
V2 = 1000 ml
V = 1000 – 10 990 ml
القوائم الدراسية التي ينتمي لها السؤال