الأجوبة
HCN + H2O ↔ CN- + H3O+
(حمض1) (أساس2) (أساس مرافق1) (حمض مرافق2)
[H3O+] = 10-PH = 10-5 mol/L
α = [H3O+]/Ca
5*10-5 = 10-5/Ca
Ca = 0.2 mol/L
[H3O+] = √Ka.Ca
10-5 = √Ka*0.2
Ka = 5*10-10
[H3O+]’ = 10-PH = 10-6 mol/L (بعد التغير)
[H3O+]’ = 10-5 mol/L (قبل التغير)
[H3O+]’/[H3O+] = 10-6/10-5 = 1/10
[H3O+]’ = [H3O+]/10
القوائم الدراسية التي ينتمي لها السؤال