Write a program in C that find the Deficient numbers (integers) between 1 to 100
- برمجة سي c
- برمجة
- 2021-05-11
- MarwaMohammed
الأجوبة
# include <stdio.h>
# include <stdbool.h>
# include <math.h>
int getSum(int n)
{
int sum = 0;
for (int i=1; i<=sqrt(n); i++)
{
if (n%i==0)
{
if (n/i == i)
sum = sum + i;
else
{
sum = sum + i;
sum = sum + (n / i);
}
}
}
sum = sum - n;
return sum;
}
bool checkDeficient(int n)
{
return (getSum(n) < n);
}
int main()
{
int n,ctr=0;
printf("\n\n The Deficient numbers between 1 to 100 are: \n");
printf(" ------------------------------------------------\n");
for(int j=1;j<=100;j++)
{
n=j;
if(checkDeficient(n)==true)
{
printf("%d ",n);
ctr++;
}
}
printf("\n The Total number of Deficient numbers are: %d \n",ctr);
}أسئلة مشابهة
القوائم الدراسية التي ينتمي لها السؤال