Write a program in C++ to find the Deficient numbers (integers) between 1 to 100
- برمجة سي بلس بلس
- برمجة
- 2021-05-13
- MarwaMohammed
الأجوبة
#include <bits/stdc++.h>
using namespace std;
int getSum(int n)
{
int sum = 0;
for (int i=1; i<=sqrt(n); i++)
{
if (n%i==0)
{
if (n/i == i)
sum = sum + i;
else
{
sum = sum + i;
sum = sum + (n / i);
}
}
}
sum = sum - n;
return sum;
}
bool checkDeficient(int n)
{
return (getSum(n) < n);
}
int main()
{
int n,ctr=0;
cout << "\n\n The Deficient numbers between 1 to 100 are: \n";
cout << " ------------------------------------------------\n";
for(int j=1;j<=100;j++)
{
n=j;
checkDeficient(n)? cout << n<<" ": cout << "";
if(checkDeficient(n))
{ctr++;}
}
cout << endl<<"The Total number of Deficient numbers are: "<<ctr << endl;
}أسئلة مشابهة
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