اكتب برنامج C للتحقق مما إذا كانت مصفوفة أعداد صحيحة لا تحتوي على 3 أو 5

#include <stdio.h>
#include <stdlib.h>
int main(void){
    int arr_size;
    int array1[] = {1, 5, 5, 5, 5};
    arr_size = sizeof(array1)/sizeof(array1[0]);
    printf("%d",test(array1, arr_size));
    int array2[] = {3, 3, 3, 3 };
    arr_size = sizeof(array2)/sizeof(array2[0]);
    printf("\n%d",test(array2, arr_size));
    int array3[] = {3, 3, 3, 5, 5, 5};
    arr_size = sizeof(array3)/sizeof(array3[0]);
    printf("\n%d",test(array3, arr_size));
    int array4[] = {1, 6, 8, 10};
    arr_size = sizeof(array3)/sizeof(array4[0]);
    printf("\n%d",test(array4, arr_size));
  }    
  int test(int nums[], int arr_size)
         {
           int three = 0, five = 0;
            for (int i = 0; i < arr_size; i++)
            {
                if (nums[i] == 3) three++;
                if (nums[i] == 5) five++;
             if (three && five) return 0;
            }
            return 1;
         }