C program to print Armstrong numbers, in the program, a user inputs two integers, and we print all Armstrong numbers between the integers. Using a for loop, we check numbers in this range. In the loop, we call function check_armstrong, which returns '1' if a number is Armstrong and '0' otherwise.
الأجوبة
#include <stdio.h>
int check_armstrong(int);
int power(int, int);
int main ()
{
int c, a, b;
printf("Input two integers\n");
scanf("%d%d", &a, &b);
for (c = a; c <= b; c++)
if (check_armstrong(c) == 1)
printf("%d\n", c);
return 0;
}
int check_armstrong(int n) {
long long sum = 0, t;
int remainder, digits = 0;
t = n;
while (t != 0) {
digits++;
t = t/10;
}
t = n;
while (t != 0) {
remainder = t%10;
sum = sum + power(remainder, digits);
t = t/10;
}
if (n == sum)
return 1;
else
return 0;
}
int power(int n, int r) {
int c, p = 1;
for (c = 1; c <= r; c++)
p = p*n;
return p;
}
output:
Input two integers
2
3
2
3
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