الأجوبة
N= total frequency = 100
The median value is the value corresponding to the 50th student.
The total number of students upto the third class is 8 + 15 + 24 = 47
The 50th item will occur in the fourth class, i.e. 131-140 which is the median class
L_m == lower class boundary of median occurs = 130.5
N/2=50
F == sum of the frequencies of the class preceding the
median class = 8 + 15 + 24 = 47
f_m == frequency of the median class = 40
c = width of median class = 10
Thus the median becomes
M=L_m+((N/2-F)/f_m )c=130.5+(50-47)/40×10=131.25
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