From the following tables write a SQL query to find those customers whose grade less than 300. Return cust_name, customer city, grade, Salesman, saleman city

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From the following tables write a SQL query to find those customers whose grade less than 300. Return cust_name, customer city, grade, Salesman, saleman city. The result should be ordered by ascending customer_id.

 

Sample table: customer

customer_id |   cust_name    |    city    | grade | salesman_id 
-------------+----------------+------------+-------+-------------
        3002 | Nick Rimando   | New York   |   100 |        5001
        3007 | Brad Davis     | New York   |   200 |        5001
        3005 | Graham Zusi    | California |   200 |        5002
        3008 | Julian Green   | London     |   300 |        5002
        3004 | Fabian Johnson | Paris      |   300 |        5006
        3009 | Geoff Cameron  | Berlin     |   100 |        5003
        3003 | Jozy Altidor   | Moscow     |   200 |        5007
        3001 | Brad Guzan     | London     |       |        5005
 salesman_id |    name    |   city   | commission 
-------------+------------+----------+------------
        5001 | James Hoog | New York |       0.15
        5002 | Nail Knite | Paris    |       0.13
        5005 | Pit Alex   | London   |       0.11
        5006 | Mc Lyon    | Paris    |       0.14
        5007 | Paul Adam  | Rome     |       0.13
        5003 | Lauson Hen | San Jose |       0.12

الأجوبة

SELECT a.cust_name,a.city,a.grade, 
b.name AS "Salesman", b.city 
FROM customer a 
LEFT OUTER JOIN salesman b 
ON a.salesman_id=b.salesman_id 
WHERE a.grade<300 
ORDER BY a.customer_id;

Output of the Query:

cust_name	city		grade	Salesman	city
Nick Rimando	New York	100	James Hoog	New York
Jozy Altidor	Moscow		200	Paul Adam	Rome
Graham Zusi	California	200	Nail Knite	Paris
Brad Davis	New York	200	James Hoog	New York
Geoff Cameron	Berlin		100	Lauson Hen	San Jose
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أسئلة مشابهة

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