يضاف (200ml) تحوي على (1.2mol) من مادة (A) إلى (200ml) تحوي على (0.8mol) من مادة (B)

لنحسب التراكيز بعد المزج:

الحجم الكلي:

200 + 200 = 400 ml

[A] = 1.2/0.4 = 3 mol/L

[B] = 0.8/0.4 = 2 mol/L

V = K[A]2[B]

V0 = 2*10-2*(3)2*(2) = 0.36 mol/L.S

2A            +           B                  →                 2C             +             D

 3                           2                                        0                             0

3-2x                      2-x                                    0+x                          2x

[D] = 0.4/0.4 = 1 mol/L

2x = 1

x = 0.5 mol/L

[A] = 3 – 1 = 2 mol/L

[B] = 2 – 0.5 = 1.5 mol/L

v = 2*10-2*(2)2*(1.5) = 12*10-2 mol/L.S

عند توقف التفاعل:

V = 0

K ≠ 0

إما:

[A] = 0

3 – 2x = 0

2x = 3

x = 1.5 mol/L

[B] = 2 – 1.5 = 0.5 mol/L

[C] = 2x = 3 mol/L

مقبول.

أو:

[B] = 0

[B] = 0

2 – x = 0

X = 2 mol/L

[A] = 3 – 2x = 3 – 4 = -1

مرفوض.