يجري عند درجة حرارة ثابتة التفاعل الأولي الممثل بالمعادلة الكيميائية الأتية: A + 3B ----> 2C

v = K[A][B]³

v0 = 0.1*(0.2)*(0.6)3

v0 = 4.32*10-3 mol/L

A + 3B ----> 2C

0.2  0.6          0

0.2-x  0.6-3x     2x

[A'] = [A]/2 = 0.1 mol/L

x = 0.1 mol/L

[A'] = 0.2 - X = 0.1 mol/L

[B'] = 0.6 - 3X = 0.3 mol/L

v' = K[A][B]^{3 =} 0.1*(0.1)*(0.3)³ = 2.7*10^-3 mol/L

A + 3B ---> 2C

0.2   0.6        0

0.2-x  0.6-3x  2x

[C] = 2x = 0.3 mol/L

x = 0.15 mol/L

[A"] = 0.2 - x = 0.2 - 0.15 = 0.05 mol/L

[B"] = 0.6 - 3x = 0.6 - 0.45 = 0.15 mol/L

v" = 0.1*(0.05)*(0.15)³ = 1.6845*10^-5 mol/L.S

v = 0

0 = k*(0.2 - x)*(0.6 - 3x)

[A] = 0

0.2 - X = 0

X = 0.2 mol/L

[B] = 0.6 - 3(0.2) = 0

[C] = 2X = 2(0.2) = 0.4 mol/L

[B] = 0

0.6 - 3X = 0

X = 0.2 mol/L

[A] = 0.2 - 0.2 = 0

[C] = 2X = 2(0.2) = 0.4 mol/L