الأجوبة
# Solve the quadratic equation ax**2 + bx + c = 0
# import complex math module
import cmath
a = 1
b = 5
c = 6
# calculate the discriminant
d = (b**2) - (4*a*c)
# find two solutions
sol1 = (-b-cmath.sqrt(d))/(2*a)
sol2 = (-b+cmath.sqrt(d))/(2*a)
print('The solution are {0} and {1}'.format(sol1,sol2))
output:
Enter a: 1 Enter b: 5 Enter c: 6 The solutions are (-3+0j) and (-2+0j)
القوائم الدراسية التي ينتمي لها السؤال