مثال على خوارزمية اقصر طريق باستخدام خوارزمية Dijkstra


الأجوبة

ابحث عن مسائل برمجة سي بلس بلس | C++ programming بالانجليزي

using namespace std;
#include <limits.h>
 
// Number of vertices in the graph
#define V 9
 
// A utility function to find the vertex with minimum distance value, from
// the set of vertices not yet included in shortest path tree

int minDistance(int dist[], bool sptSet[])
{

   

    // Initialize min value

    int min = INT_MAX, min_index;
 

    for (int v = 0; v < V; v++)

        if (sptSet[v] == false && dist[v] <= min)

            min = dist[v], min_index = v;
 

    return min_index;
}
 
// A utility function to print the constructed distance array

void printSolution(int dist[])
{

    cout <<"Vertex \t Distance from Source" << endl;

    for (int i = 0; i < V; i++)

        cout  << i << " \t\t"<<dist[i]<< endl;
}
 
// Function that implements Dijkstra's single source shortest path algorithm
// for a graph represented using adjacency matrix representation

void dijkstra(int graph[V][V], int src)
{

    int dist[V]; // The output array.  dist[i] will hold the shortest

    // distance from src to i
 

    bool sptSet[V]; // sptSet[i] will be true if vertex i is included in shortest

    // path tree or shortest distance from src to i is finalized
 

    // Initialize all distances as INFINITE and stpSet[] as false

    for (int i = 0; i < V; i++)

        dist[i] = INT_MAX, sptSet[i] = false;
 

    // Distance of source vertex from itself is always 0

    dist[src] = 0;
 

    // Find shortest path for all vertices

    for (int count = 0; count < V - 1; count++) {

        // Pick the minimum distance vertex from the set of vertices not

        // yet processed. u is always equal to src in the first iteration.

        int u = minDistance(dist, sptSet);
 

        // Mark the picked vertex as processed

        sptSet[u] = true;
 

        // Update dist value of the adjacent vertices of the picked vertex.

        for (int v = 0; v < V; v++)
 

            // Update dist[v] only if is not in sptSet, there is an edge from

            // u to v, and total weight of path from src to  v through u is

            // smaller than current value of dist[v]

            if (!sptSet[v] && graph[u][v] && dist[u] != INT_MAX

                && dist[u] + graph[u][v] < dist[v])

                dist[v] = dist[u] + graph[u][v];

    }
 


    printSolution(dist);
}
 

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